Data Interpretation MCQ Questions and Answers - Bar Chart

Total accidents = 230 + 150 + 120 + 160 + 40 + 200 + 100 = 1000
Percentage of accidents involving two wheelers = $$\frac{230}{1000}$$ × 100 = 23%
Percentage of accidents involving two wheelers and other subjects = $$\frac{770 \times 100}{1000}$$   = 77%
∴ Required difference = 77 - 23 = 54%

Required Percentage
$$\eqalign{ & = \left( {\frac{{40 + 200}}{{1000}}} \right) \times 100 \cr & = \frac{{24000}}{{1000}} \cr & = 24\% \cr} $$

Two wheelers + Cars + Buses + Stationary vehicles
= 230 + 150 + 120 + 100
= 600
∴ $$\frac{600}{1000}$$ × 100 = 60%

Required difference
= $$\frac{160 - 120}{1000}$$   × 100
= 4%

$$\eqalign{ & \therefore {360^ \circ } = 1000{\text{ Accidents}} \cr & \,\,\,\,\,{1^ \circ } = \frac{{1000}}{{{{360}^ \circ }}} \cr &\,\,\,\,\, {36^ \circ } = \frac{{1000}}{{{{360}^ \circ }}} \times {36^ \circ } \cr & \,\,\,\,\,\,\,\,\,\,\,\,\, = 100{\text { Accidents}} \cr} $$
It is the accidents of Stationary vehicles