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Data Interpretation MCQ Questions and Answers - Bar Chart

Learn Bar Chart Data Interpretation mcq question and answers with easy and logical explanations Page-16 section-1

Directions (1 - 5): Study the following pie-chart and bar graph and answer the questions that follows:
Percentage-wise distribution of Teachers in 6 Districts.
Direction image of Bar Chart chapter
Number of males in each district out of 4500 Teachers.
Direction image of Bar Chart chapter
1
What is the total number of male teachers in District F, female teachers District C and female teachers in District B together?
Discuss
Answer & Solution
$$\eqalign{ & \text{Total number of teachers in:} \cr & \text{A → } \frac{14}{100}\times4500 = 630\cr & \text{B → } \frac{16}{100}\times4500 = 720\cr & \text{C → } \frac{28}{100}\times4500 = 1260\cr & \text{D → } \frac{15}{100}\times4500 = 675\cr & \text{E → } \frac{21}{100}\times4500 = 945\cr & \text{F → } \frac{6}{100}\times4500 = 270\cr} $$

A B C D E F
Males 200 400 600 100 500 100
Females 430 320 660 575 445 170

Total number of male teacher in F, female teacher in C and female teacher in B
= 100 + 660 + 320
= 1080
2
In which district is the number of male teachers more than the number of female teachers?
Discuss
Answer & Solution
$$\eqalign{ & \text{Total number of teachers in:} \cr & \text{A → } \frac{14}{100}\times4500 = 630\cr & \text{B → } \frac{16}{100}\times4500 = 720\cr & \text{C → } \frac{28}{100}\times4500 = 1260\cr & \text{D → } \frac{15}{100}\times4500 = 675\cr & \text{E → } \frac{21}{100}\times4500 = 945\cr & \text{F → } \frac{6}{100}\times4500 = 270\cr} $$

A B C D E F
Males 200 400 600 100 500 100
Females 430 320 660 575 445 170

Clearly, the number of male teachers is more than the number of female teachers in B and E.
3
What is the ratio of the number of male teachers in District C to the number of female teachers in District B?
Discuss
Answer & Solution
$$\eqalign{ & \text{Total number of teachers in:} \cr & \text{A → } \frac{14}{100}\times4500 = 630\cr & \text{B → } \frac{16}{100}\times4500 = 720\cr & \text{C → } \frac{28}{100}\times4500 = 1260\cr & \text{D → } \frac{15}{100}\times4500 = 675\cr & \text{E → } \frac{21}{100}\times4500 = 945\cr & \text{F → } \frac{6}{100}\times4500 = 270\cr} $$

A B C D E F
Males 200 400 600 100 500 100
Females 430 320 660 575 445 170

(Number of male teachers in C) : (Number of female teachers in B)
= 600 : 320
= 15 : 8
4
The number of female teachers in District D is approximately what percent of the total number of teachers (both male & female) in District A?
Discuss
Answer & Solution
$$\eqalign{ & \text{Total number of teachers in:} \cr & \text{A → } \frac{14}{100}\times4500 = 630\cr & \text{B → } \frac{16}{100}\times4500 = 720\cr & \text{C → } \frac{28}{100}\times4500 = 1260\cr & \text{D → } \frac{15}{100}\times4500 = 675\cr & \text{E → } \frac{21}{100}\times4500 = 945\cr & \text{F → } \frac{6}{100}\times4500 = 270\cr} $$

A B C D E F
Males 200 400 600 100 500 100
Females 430 320 660 575 445 170

Female teacher in D = 575
Total number of teacher in A
= 200 + 430
= 630
∴ Required percentage
$$\eqalign{ & = \left(\frac{575}{630}\times100\right)\% \cr & = \frac{5750}{63}\% \cr & = 91.2\% \cr & \approx 90\% \cr} $$
5
What is the difference between the number of female teachers in District F and the total number of teachers (both male and female) in District E?
Discuss
Answer & Solution
$$\eqalign{ & \text{Total number of teachers in:} \cr & \text{A → } \frac{14}{100}\times4500 = 630\cr & \text{B → } \frac{16}{100}\times4500 = 720\cr & \text{C → } \frac{28}{100}\times4500 = 1260\cr & \text{D → } \frac{15}{100}\times4500 = 675\cr & \text{E → } \frac{21}{100}\times4500 = 945\cr & \text{F → } \frac{6}{100}\times4500 = 270\cr} $$

A B C D E F
Males 200 400 600 100 500 100
Females 430 320 660 575 445 170

Number of female teachers in F = 170
Total number of teachers in E
= 500 + 445
= 945
∴ Required difference
= 945 - 170
= 775