Determine output #include &lt stdio h void main() char p =...

This question belongs to C Program Pointer

Pointer

Determine output:

#include <stdio.h>
void main()
{
      char *p = NULL;
      char *q = 0;
      if(p)
            printf(" p ");
      else
            printf("nullp");
      if(q)
            printf("q");
      else
            printf(" nullq");
}

A) p q B) Depends on the compiler C) x nullq where x can be p or nullp depending on the value of NULL D) nullp nullq

Answer & Solution

Correct Answer: Option D

char *p = NULL is same as char *q = 0.
In both declarations p and q are initialized to null.

Question posted by Examveda

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3 Comments

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Vedant Kulkarni 6 years ago

They are using 64 bit compiler so the size of pointer in 64 bit compiler is 8 byte...
Is it okay frinds???

Manuja Krishna 8 years ago

Please anyone explain me gow it goes to else loop ,i am getting it

Jagadish Jaggu 9 years ago

Here if (p) that p gives address n not a value and how it goes to else

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Determine output #include &lt stdio h void main() char p =...

Determine output: #include <stdio.h> void main() { char *p = NULL; char *q = 0; if(p) printf(" p "); else printf("nullp"); if(q) printf("q"); else printf(" nullq"); }

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Related Questions on Pointer

Determine output:
`#include <stdio.h> void main() { char p = NULL; char q = 0; if(p) printf(" p "); else printf("nullp"); if(q) printf("q"); else printf(" nullq"); }`