Dinesh bought two radios for Rs. 1920. He sold one at a profit of 20% and other at a loss of $$6\frac{2}{3}$$% . If the selling price of both radios are same, then find the cost price of both radios = ?
A. Rs. 800 and Rs. 1120
B. Rs. 840 and Rs. 1080
C. Rs. 860 and Rs. 1060
D. Rs. 900 and Rs. 1020
Answer: Option B
Solution(By Examveda Team)
Let first radio CP is x second radio CP is 1920 - xAs is given,
$$x \times \frac{{\left( {100 + 20} \right)}}{{100}} = \left( {1920 - x} \right) \times $$ $$\frac{{\left( {100 - \frac{{20}}{3}} \right)}}{{100}}$$
$$\eqalign{ & 120 \times x = \left( {1920 - x} \right) \times \left( {\frac{{280}}{3}} \right) \cr & 360 \times x = \left( {1920 - x} \right) \times 280 \cr & 640 \times x = 1920 \times 28 \cr & \therefore x = 840 \cr} $$
Hence, second radio cp is 1920 - x
= 1920 - 840
= 1080
CP of both Radio = 840 and 1080
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Comments ( 1 )
Related Questions on Profit and Loss
A. 45 : 56
B. 45 : 51
C. 47 : 56
D. 47 : 51
A. Rs. 2600
B. Rs. 2700
C. Rs. 2800
D. Rs. 3000
A. A neither losses nor gains
B. A makes a profit of 11%
C. A makes a profit of 20%
D. B loses 20%
A. Rs. 3,750
B. Rs. 3,250
C. Rs. 2,750
D. Rs. 2,250
How come 280/3