Fill in the blank to complete the code.

#include<stdio.h>
int main()
{
      int coins[10]={1,3,4},lookup[100000];
      int i,j,tmp,num_coins = 3,sum=100;
      lookup[0]=0;
      for(i = 1; i <= sum; i++)
      {
	   int min_coins = i;
	   for(j = 0;j < num_coins; j++)
	   {
	        tmp = i - coins[j];
	        if(tmp < 0)
	         continue;
	        if(lookup[tmp] < min_coins)
	       ______________;
	   }
	   lookup[i] = min_coins + 1;
      }
      printf("%d",lookup[sum]);
      return 0;
}

A. lookup[tmp] = min_coins

B. min_coins = lookup[tmp]

C. break

D. continue

Answer: Option B