Find the selling price of goods if two salesmen claim to make 25% profit each, one calculating it on cost price while another on the selling price, the difference in the profits earned being Rs. 100 and selling price being the same in both the cases?
A. Rs. 1200
B. Rs. 1600
C. Rs. 2400
D. Rs. 2500
E. Rs. 3000
Answer: Option A
Solution(By Examveda Team)
Let CP's be Rs. 1000 each, their respective SP will be,1000 == 25%↑ ⇒ 1250 [person calculating profit on the CP]
1000 == 33.33%↑ ⇒ 1333.33 [The person calculating his profit on SP: 25% of SP = 33.33% of CP]
The difference turned out to be = 83.33. This has occured when we have assumed the CP as 1000. But, we are given difference of Rs. 100
So, on comparing,
83.33 = 1000
1 = $$\frac{{1000}}{{83.33}}$$
100 = $$\frac{{1000}}{{83.33}} \times 100$$ = Rs. 1200
This Question Belongs to Arithmetic Ability >> Profit And Loss
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Comments ( 9 )
Related Questions on Profit and Loss
A. 45 : 56
B. 45 : 51
C. 47 : 56
D. 47 : 51
A. Rs. 2600
B. Rs. 2700
C. Rs. 2800
D. Rs. 3000
A. A neither losses nor gains
B. A makes a profit of 11%
C. A makes a profit of 20%
D. B loses 20%
A. Rs. 3,750
B. Rs. 3,250
C. Rs. 2,750
D. Rs. 2,250
25%= 1/4
CP SP P
1) 4 5 1
2) 3 4 1
GIiven that both goods have same SP
1) 4×4 5×4 1×4
2) 3×5 4×5 1×5
1) 16 20 4
2) 15 20 5
Diffrence between profit is 100
But we have, 5-4=1
1= 100
Then 20= 2000
Hence, 2000 is right option.
Sales man 1(SM1) :-
He takes profit as 25% of CP
CP of SM1= x
SP of SM1 = y
x + 25%x = y..............................................(A)
125%x = y
y = 125x/100
y = 5x/4.................................................(1)
Sales man 2 (SM2) :-
He takes profit as 25% of SP
CP of SM2 = z
SP of SM2 = y (because selling prices of two sales man are same)
z + 25%y = y.......................................(B)
z + 25y/100 = y
z + y/4 = y
z = y - y/4
z = 3y/4
y = 4z/3...........................................(2)
equate (1) and (2)
5x/4 = 4z/3
x/z = 16/15
So, x/z = 16a/15a ( create new variable "a" because we didn't know the correct value)
x = 16a
z = 15a
substitute x in (A)
16a + 25% (16a) = y
y = 16a + 4a ( here "4a" is profit for SM1)
y = 20a
substitute y, z in (B)
15a + 25% (20a) = 20a
15a + 5a = 20a ( here "5a" is profit for SM2)
Difference between profit of two sales mans is 100
So, 5a - 4a = 100
a = 100
Then,
y = 20a = 20 (100) = 2000
x = 16a = 16 (100) = 1600
z = 15a = 15 (100) = 1500
wrong ans
According to solution Question is wrong It should same Cost pice .
But according to question It's answer should be 2000
easiest way solve such q.-:
given gain = 25% = 1/4
now case 1 , calculating profit on cp.
let cp= 4x so profit = 4x*1/4=x so sp= 4x+x=5x
now case 2, calculating on sp
let sp=4y so profit = y
now ATQ
5x=4y and y-x=100, solve eq. you get x=400 so sp =5x=5*400=2000
the q. is different and solution is different. options are also wrong. this q. has been asked in ssc exam earlier its ans is rs 2000 selling price. plz dont confuse students
But it is given that the selling price is same in both the cases. why are you taking two different selling prices and same cost prices. In this case cost prices will be different.
Second person is calculating 25% of his profit on the Selling price.
And the selling price is
1000 + 25% of 1000 = 1250.
Now, 25% of 1250 = 312.5.
25% = 312.5
So, 100% = 1333.33
Thus, the actual profit on the Cost price would be,
(333.33*100)/1000 = 33.33%.
Now, Is it clear @Divya?
please explain the 2nd line 33.33% of cp in detail. i didnt got that point at all