For a peak discharge of 0.0157 cumec, with a velocity of 0.9 m/sec, the diameter of the sewer main, is
A. 10 cm
B. 12 cm
C. 15 cm
D. 18 cm
Answer: Option C
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Q=A×V
15.7=(π÷4)D^2 × 0.9
D^2=222.222
D=√222.222
D=14.90~~~~~15cm
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