For slaking of 10 kg of CaO, the theoretical amount of water is
A. 2.2 kg
B. 1.5 kg
C. 3.2 kg
D. None of these
Answer: Option C
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The slaking reaction is:
CaO + H2O = Ca(OH)2
Molecular weight of CaO = 56 g/mol
Molecular weight of H₂O = 18 g/mol
Therefore, 56 g of CaO requires 18 g of water.
For 10 kg (10,000 g) of CaO:
(18/56)* 10 = 3.21kg
Although the theoretical water requirement is 3.2 kg per 10 kg of CaO, in practice about 2–3 times this amount is often used to ensure complete slaking.