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For slaking of 10 kg of CaO the theoretical amount of...

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For slaking of 10 kg of CaO, the theoretical amount of water is

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Correct Answer: Option C
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Riju Chakraborty
Riju Chakraborty 4 months ago
The slaking reaction is:
CaO + H2O = Ca(OH)2
Molecular weight of CaO = 56 g/mol
Molecular weight of H₂O = 18 g/mol
Therefore, 56 g of CaO requires 18 g of water.

For 10 kg (10,000 g) of CaO:
(18/56)* 10 = 3.21kg
Although the theoretical water requirement is 3.2 kg per 10 kg of CaO, in practice about 2–3 times this amount is often used to ensure complete slaking.
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