Given that (1² + 2² + 3² + ..... + 20²) = 2870, the value of (2² + 4² + 6² + ... + 40² ) is :

A. 2870

B. 5740

C. 11480

D. 28700

Answer: Option C

Solution(By Examveda Team)

= (2² +4² +6² + ..... + 40²)
= (1 × 2)² +(2 × 2)² +(2 × 3)² + ..... + (2 × 20)²
= 2² × (1² + 2² + 3² + ..... + 20²)
= (4 × 2870)
= 11480