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This question belongs to Arithmetic Ability Number System
Number System
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How many $$\frac{1}{6}$$ of together make $${\text{41}}\frac{2}{3}$$ ?

Answer & Solution
Correct Answer: Option C
$$\frac{{41\frac{2}{3}}}{{\frac{1}{6}}} = \frac{{125}}{3} \times \frac{6}{1} = 250{\text{ times}}$$
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