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If 3x2 - 9x + 3 = 0, then what is the value of $${\left( {x + \frac{1}{x}} \right)^3}?$$
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& 3{x^2} - 9x + 3 = 0 \cr
& 3x\left( {x - 3 + \frac{1}{x}} \right) = 0,\,x + \frac{1}{x} = 3 \cr
& \therefore \,{\left( {x + \frac{1}{x}} \right)^3} = {\left( 3 \right)^3} = 27 \cr} $$
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