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Square Root and Cube Root
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If $$\sqrt 5 = 2.236, $$   then the value of $$\frac{{\sqrt 5 }}{2}$$ $$ - $$ $$\frac{{10}}{{\sqrt 5 }}$$ $$ + $$ $$\sqrt {125} $$   is equal to :

Answer & Solution
Correct Answer: Option B
$$\eqalign{ & \frac{{\sqrt 5 }}{2} - \frac{{10}}{{\sqrt 5 }} + \sqrt {125} \, \cr & = \frac{{{{\left( {\sqrt 5 } \right)}^2} - 20 + 2\sqrt 5 \times 5\sqrt 5 }}{{2\sqrt 5 }} \cr & = \frac{{5 - 20 + 50}}{{2\sqrt 5 }} \cr & = \frac{{35}}{{2\sqrt 5 }} \times \frac{{\sqrt 5 }}{{\sqrt 5 }} \cr & = \frac{{35\sqrt 5 }}{{10}} \cr & = \frac{{7 \times 2.236}}{2} \cr & = 7 \times 1.118 \cr & = 7.826 \cr} $$
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