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If a + 1, 2a + 1, 4a - 1 are in A.P., then the value of a is:
Answer & Solution
Correct Answer:
Option
B
Let 1st term = x = a + 1,
2nd term = y = 2a + 1 and
3rd term = z = 4a - 1
⇒ y - x = z - y
⇒ 2y = x + z
⇒ 2(2a + 1) = a + 1 + 4a - 1
⇒ 4a + 2 = 5a
⇒ a = 2
2nd term = y = 2a + 1 and
3rd term = z = 4a - 1
⇒ y - x = z - y
⇒ 2y = x + z
⇒ 2(2a + 1) = a + 1 + 4a - 1
⇒ 4a + 2 = 5a
⇒ a = 2
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