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If a = b × $$\frac{{d}}{{c}}$$; b, c and d are increased by 10%, then by how much does a increase ?
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& {\text{Let,}} \cr
& B = 110\% {\text{ of }}b = \frac{{11b}}{{10}}{\text{ }} \cr
& C = 110\% {\text{ of }}c = \frac{{11c}}{{10}} \cr
& D = 110\% {\text{ of }}d = \frac{{11d}}{{10}} \cr
& {\text{Then,}} \cr
& A = B \times \frac{D}{C} \cr
& A = \frac{{11b}}{{10}} \times \frac{{11d}}{{10}} \times \frac{{10}}{{11c}} \cr
& A = \frac{{11bd}}{{10c}} \cr
& A = \frac{{11}}{{10}}a \cr
& A = \frac{{110}}{{100}}a \cr
& A = 110\% {\text{ of }}a \cr
& \therefore {\text{ Increase }}\% = 10\% \cr} $$
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