Electromagnetic Field Theory

If C is a closed curve enclosing a surface S, then the magnetic field intensity $$\overrightarrow H $$, the current density $$\overrightarrow J $$ and the electric flux density $$\overrightarrow D $$ are related by

A) $$\iint\limits_S {\overrightarrow H .\overrightarrow d s = }\oint\limits_C {\left( {J + \frac{{\partial \overrightarrow D }}{{\partial t}}} \right)} .\overrightarrow d l$$ B) $$\int\limits_C {\overrightarrow H .\overrightarrow d \ell = \mathop{{\int\!\!\!\!\!\int}\mkern-21mu \bigcirc}\limits_S {\left( {\overrightarrow J + \frac{{\partial \overrightarrow D }}{{\partial t}}} \right)} } .\overrightarrow d s$$ C) $$\mathop{{\int\!\!\!\!\!\int}\mkern-21mu \bigcirc}\limits_S {\overrightarrow H .\overrightarrow d } s = \int\limits_C {\left( {\overrightarrow J + \frac{{\partial \overrightarrow D }}{{\partial t}}} \right)} .\overrightarrow d l$$ D) $$\oint\limits_C {\overrightarrow H .\overrightarrow d l} = \iint\limits_S {\left( {\overrightarrow J + \frac{{\partial \overrightarrow D }}{{\partial t}}} \right)}.\overrightarrow d s$$

Answer & Solution

Correct Answer: Option D

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If C is a closed curve enclosing a surface S then...

If C is a closed curve enclosing a surface S, then the magnetic field intensity $$\overrightarrow H $$, the current density $$\overrightarrow J $$ and the electric flux density $$\overrightarrow D $$ are related by

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If C is a closed curve enclosing a surface S then...

If C is a closed curve enclosing a surface S, then the magnetic field intensity $$\overrightarrow H $$, the current density $$\overrightarrow J $$ and the electric flux density $$\overrightarrow D $$ are related by

Join the Discussion

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