If Dp is the equivalent diameter of a non-spherical particle, Vp its volume and Sp its surface area, then its sphericity is Φs is defined by
A. Φs $$ = \frac{{6{{\text{V}}_{\text{p}}}}}{{{{\text{D}}_{\text{p}}}{{\text{S}}_{\text{p}}}}}$$
B. Φs $$ = \frac{{{{\text{V}}_{\text{p}}}}}{{{{\text{D}}_{\text{p}}}{{\text{S}}_{\text{p}}}}}$$
C. Φs $$ = \frac{{6{{\text{D}}_{\text{p}}}{{\text{S}}_{\text{p}}}}}{{{{\text{V}}_{\text{p}}}}}$$
D. Φs $$ = \frac{{{{\text{D}}_{\text{p}}}{{\text{S}}_{\text{p}}}}}{{{{\text{V}}_{\text{p}}}}}$$
Answer: Option A
This Question Belongs to Chemical Engineering >> Mechanical Operations
for a spherical particle of diameter dp φs is