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If in the following figure (not to scale), ∠DAB + ∠CBA = 90°, BC = AD, AB = 20 cm, CD = 10 cm
then the area of the quadrilateral ABCD is:
If in the following figure (not to scale), ∠DAB + ∠CBA = 90°, BC = AD, AB = 20 cm, CD = 10 cm
then the area of the quadrilateral ABCD is:
Answer & Solution
Correct Answer:
Option
D
$${\text{Area of ABCD}} = \frac{1}{2} \times 30 \times 5 = 75{\text{ c}}{{\text{m}}^2}$$
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