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If k, 2k – 1 and 2k + 1 are three consecutive terms of an AP, the value of k is
Answer & Solution
Correct Answer:
Option
B
(2K - 1) - K = (2K + 1) - (2K - 1)
2K - 1 - K = 2
⇒ K = 3
2K - 1 - K = 2
⇒ K = 3
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