If straight sides of a triangular section of a lined canal with circular bottom of radius R, make an angle θ with horizontal, the area of its cross-section, is
A. R (θ + tan θ)
B. R (θ + cot θ)
C. R2 (θ + tan θ)
D. R2 (θ + cot θ)
Answer: Option D
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Area = R^2(θ + cot θ)
I didn't understand... Can anyone plz explain