If the numerator of a fraction is increased by 15% and denominator is decreased by 20%, then the fraction, so obtained, is $$\frac{{17}}{{65}}.$$  What is the original fraction?

A. $$\frac{{281}}{{1495}}$$

B. $$\frac{{278}}{{1495}}$$

C. $$\frac{{267}}{{1495}}$$

D. $$\frac{{272}}{{1495}}$$

Answer: Option D

Solution(By Examveda Team)

$$\eqalign{ & {\text{Let fraction}} = \frac{x}{y} \cr & \frac{{x\left( {115} \right)}}{{y \times 80}} = \frac{{17}}{{65}} \cr & \frac{x}{y} = \frac{{17}}{{65}} \times \frac{{16}}{{23}} = \frac{{272}}{{1495}} \cr} $$