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If the numerator of a fraction is increased by 15% and denominator is decreased by 20%, then the fraction, so obtained, is $$\frac{{17}}{{65}}.$$ What is the original fraction?
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& {\text{Let fraction}} = \frac{x}{y} \cr
& \frac{{x\left( {115} \right)}}{{y \times 80}} = \frac{{17}}{{65}} \cr
& \frac{x}{y} = \frac{{17}}{{65}} \times \frac{{16}}{{23}} = \frac{{272}}{{1495}} \cr} $$
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