If the numerator of a fraction is increased by 15% and denominator is decreased by 20%, then the fraction, so obtained, is $$\frac{{17}}{{65}}.$$ What is the original fraction?
A. $$\frac{{281}}{{1495}}$$
B. $$\frac{{278}}{{1495}}$$
C. $$\frac{{267}}{{1495}}$$
D. $$\frac{{272}}{{1495}}$$
Answer: Option D
Solution (By Examveda Team)
$$\eqalign{ & {\text{Let fraction}} = \frac{x}{y} \cr & \frac{{x\left( {115} \right)}}{{y \times 80}} = \frac{{17}}{{65}} \cr & \frac{x}{y} = \frac{{17}}{{65}} \times \frac{{16}}{{23}} = \frac{{272}}{{1495}} \cr} $$This Question Belongs to Arithmetic Ability >> Percentage
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