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If x = 0.5 and y = 0.2, then the value of $$\sqrt {0.6} \times {\left( {3y} \right)^x}$$ is equal to?
Answer & Solution
Correct Answer:
Option
C
$$\eqalign{
& x = 0.5 \cr
& y = 0.2 \cr
& \sqrt {0.6} \times {\left( {3y} \right)^x}{\text{ }} \cr
& = \sqrt {0.6} \times {\left( {3 \times 0.2} \right)^{0.5}}{\text{ }} \cr
& = \sqrt {0.6} \times \sqrt {0.6} \cr
& = 0.6 \cr} $$
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