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If $$x + \frac{{16}}{x} = 8,$$ then the value of $${x^2} + \frac{{32}}{{{x^2}}}$$ is:
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& x + \frac{{16}}{x} = 8 \cr
& {\text{at }}x = 4{\text{ it satisfy}} \cr
& {x^2} + \frac{{32}}{{{x^2}}} = {4^2} + \frac{{32}}{{{4^2}}} \cr
& = 16 + 2 \cr
& = 18 \cr} $$
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