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If x, y, z and w be the digits of a number beginning from the left, the number is :

A. xyzw

B. wzyx

C. x + 10y + 100z + 1000w

D. 103x + 102y + 10z + w

Answer: Option D

Solution(By Examveda Team)

Let the thousand's, hundred's, ten's, and one's digits be x, y, z, w respectively.
Then, the number is
1000x + 100y + 10z + w
= 103x + 102y + 10z + w

This Question Belongs to Arithmetic Ability >> Number System

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