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This question belongs to Arithmetic Ability Percentage
Percentage
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In a test, minimum passing percentage for girls and boys is 35% and 40% respectively. A boy scored 483 marks and failed by 117 marks. What is the minimum passing marks for girls ?

Answer & Solution
Correct Answer: Option E
Let the maximum marks be x
Then, 40% of x = 483 + 117
⇒ $$\frac{{40x}}{{100}}$$ = 600
⇒ x = $$\left( {\frac{{600 \times 100}}{{40}}} \right)$$
⇒ x = 1500
∴ Minimum passing marks for girls :
= 35% of 1500
= $$\left( {\frac{{35}}{{100}} \times 1500} \right)$$
= 525
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