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In a town, the population was 8000. In one year, male population increased by 10% and female population increased by 8% but the total population increased by 9%. The number of males in the town was :
Answer & Solution
Correct Answer:
Option
A
Note :In such type of questions use allegation method to save your valuable time.
Required number of males
= $$\frac{8000}{(1 + 1)}$$ × 1
= 4000
Required number of males
= $$\frac{8000}{(1 + 1)}$$ × 1
= 4000
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