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This question belongs to Arithmetic Ability Percentage
Percentage
?

In an examination, 35% candidates failed in one subject and 42% failed in another subject while 15% failed in both the subjects. If 2500 candidates appeared at the examination, how many passed in either subject but not in both ?

Answer & Solution
Correct Answer: Option B
Failed in 1st subject = $$\frac{35}{100}$$ × 2500 = 875
Failed in 2nd subject = $$\frac{42}{100}$$ × 2500 = 1050
Failed in both = $$\frac{15}{100}$$ × 2500 = 375
Failed in 1st subject only = (875 - 375) = 500
Failed in 2nd subject only = (1050 - 375) = 675
∴ Passed in 2nd only + Passed in 1st only
= (675 + 500)
= 1175
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