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This question belongs to Arithmetic Ability Percentage
Percentage
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In an examination 36% are pass marks. If an examine gets 17 marks and fails by 10 marks, what are the maximum marks?

Answer & Solution
Correct Answer: Option B
Pass mark = (17 + 10) = 27
Let maximum marks be x
Then 36% of x = 27
Or, $$\frac{{36{\text{x}}}}{{100}}$$ = 27
Or, 36x = 2700
Hence, x = 75
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