ExamVeda
Login
Home
This question belongs to Arithmetic Ability Percentage
Percentage
?

In an examination A got 25% marks more than B, B got 10% less than C and C got 25% more than D. If D got 320 marks out of 500, the marks obtained by A were :

Answer & Solution
Correct Answer: Option B
Marks obtained by D = 320
Marks obtained by C
= 320 × $$\frac{125}{100}$$ = 400
Marks obtained by B
= 400 × $$\frac{(100 - 10)}{100}$$   = 360
Marks obtained by A
= 360 × $$\frac{125}{100}$$ = 450
Hence, required marks obtained by A = 450
Examveda
Question posted by Examveda
Community

Join the Discussion

No comments yet Be the first to discuss this question.