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In an examination, B obtained 20%, more marks than those obtained by A, and A obtained 10% less marks than those obtained by C. D obtained 20% marks than those obtained by C. By what percentage are the marks obtained by D more than those obtained by A?
Answer & Solution
Correct Answer:
Option
D
Let C marks = 100
More = 120 - 90 = 30
More % $$ = \frac{{30}}{{90}} \times 100 = 33\frac{1}{3}\% $$
More = 120 - 90 = 30
More % $$ = \frac{{30}}{{90}} \times 100 = 33\frac{1}{3}\% $$
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