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This question belongs to Arithmetic Ability Percentage
Percentage
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In an examination it is required to get 296 of the total maximum aggregate marks to pass. A student gets 259 marks and is decided failed. The difference of marks obtained by the student and that required to pass is 5%. What are the maximum aggregate marks a students can get ?

Answer & Solution
Correct Answer: Option B
Let the maximum marks be = x
Then, 5% of x = 296 - 259
⇒ $$\frac{5x}{100}$$ = 37
⇒ x = $$\frac{37 × 100}{5}$$
⇒ x = 740
Examveda
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