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This question belongs to Arithmetic Ability Percentage
Percentage
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In an examination it is required to get 36% of the aggregate marks to pass. A student gets 198 marks and is declared failed by 36 marks. What is the maximum aggregate marks a student can get ?

Answer & Solution
Correct Answer: Option C
Let the maximum marks be x
Then,
36% of x = 198 + 36
⇒ $$\frac{36x}{100}$$ = 234
⇒ x = $$\frac{234 × 100}{36}$$
⇒ x = 650
Examveda
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