In an isosceles ΔABC, AD is the median to the unequal side meeting BC at D. DP is the angle bisector of ∠ADB and PQ is drawn parallel to BC meeting AC at Q. Then the measure of ∠PDQ is

A. 130°

B. 90°

C. 180°

D. 45°

Answer: Option B

Solution(By Examveda Team)

∠PDQ = 45° + 45° = 90°