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In an isosceles ABC AD is the median to the unequal...

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Geometry
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In an isosceles ΔABC, AD is the median to the unequal side meeting BC at D. DP is the angle bisector of ∠ADB and PQ is drawn parallel to BC meeting AC at Q. Then the measure of ∠PDQ is

Answer & Solution
Correct Answer: Option B
Geometry mcq question image
∠PDQ = 45° + 45° = 90°
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