In how many ways can 6 green toys and 6 red toys be arranged, such that 2 particular red toys are never together whereas 2 particular green toys are always together?
A. 11! × 2!
B. 9! × 90
C. 4 × 10!
D. 18 × 10!
Answer: Option D
Solution(By Examveda Team)
Considering two green toys that are to be together as one unit. We can arrange the 6 green toys and the remaining 4 red toys (excluding the 2 who are not to be together) is: = 9! × 2! × 10C2 × 2!= 18 × 10!
This Question Belongs to Arithmetic Ability >> Permutation And Combination
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