In how many ways can 6 green toys and 6 red toys be arranged, such that 2 particular red toys are never together whereas 2 particular green toys are always together?
A. 11! × 2!
B. 9! × 90
C. 4 × 10!
D. 18 × 10!
Answer: Option D
Solution(By Examveda Team)
Considering two green toys that are to be together as one unit. We can arrange the 6 green toys and the remaining 4 red toys (excluding the 2 who are not to be together) is: = 9! × 2! × 10C2 × 2!= 18 × 10!
Related Questions on Permutation and Combination
A. 3! 4! 8! 4!
B. 3! 8!
C. 4! 4!
D. 8! 4! 4!
A. 7560,60,1680
B. 7890,120,650
C. 7650,200,4444
D. None of these
A. 8 × 9!
B. 8 × 8!
C. 7 × 9!
D. 9 × 8!
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