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In how many ways can seven friends be seated in a row having 35 seats, such that no two friends occupy adjacent seats?
Answer & Solution
Correct Answer:
Option
A
First let us consider the 28 unoccupied seats.
They create 29 slots - one on the left of each seat and one on the right of the last one.
We can place the 7 friends in any of these 29 slots i.e. 29P7 ways.
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Loginwhich means a min of 6 empty seats between them if they are sitting closest to each other....like X_X_X_X (X=occupied seat, _ = empty seat )......
This leaves 29 available seats. 7 friends can occupy them 29P7 ways
In how many ways can seven friends be seated in a row having 40 seats, such that no to friends occupy adjacent seats?
this is a solve answer.
Help me.