In the given figure, if AC, DE are parallel and ∠CAB = 38°, then the value of ∠ABC + 5∠CBD is:
A. 158°
B. 178°
C. 218°
D. 196°
Answer: Option C
Solution (By Examveda Team)
If AC || BD,
2a + b + a = 180° . . . . . . (1)
2a = 38°
a = 19°
From equation (1)
2 × 19° + b + 19° = 180°
b = 123°
Now,
∠ABC + 5∠CBD
= 123° + 5 × 19°
= 218°
This Question Belongs to Arithmetic Ability >> Geometry
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