In the given figure, PQRSTU is a regular hexagon of side 12 cm. What is the area (in cm²) of triangle SQU?

$$\eqalign{ & {\text{Area of }}\Delta {\text{SQU}} = \frac{1}{2}{\text{ area of hexagon}} \cr & = \frac{1}{2} \times \left[ {6 \times \frac{{\sqrt 3 }}{4}{{\left( {12} \right)}^2}} \right] \cr & = \frac{1}{2} \times 216\sqrt 3 \cr & = 108\sqrt 3 {\text{ c}}{{\text{m}}^2} \cr} $$