Incentre of ΔABC is I. ∠ABC = 90° and ∠ACB = 70°. Then ∠BIC is

A. 115°

B. 100°

C. 110°

D. 105°

Answer: Option B

Solution(By Examveda Team)

∵ Sum of all angles of a triangle = 180°
So, ∠BAC = 180° - (90° + 70°) = 20°

So, ∠BIC = 90° + $$\frac{1}{2}$$∠A
∠BIC = 90° + $$\frac{1}{2}$$ × 20°
∠BIC = 100°