?
It is being given that (232 + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number?
Answer & Solution
Correct Answer:
Option
D
Let 232 = x.
Then,
(232 + 1) = (x + 1)
Let (x + 1) be completely divisible by the natural number N.
Then,
(296 + 1)
= [(232)3 + 1]
= (x3 + 1)
= (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.
Then,
(232 + 1) = (x + 1)
Let (x + 1) be completely divisible by the natural number N.
Then,
(296 + 1)
= [(232)3 + 1]
= (x3 + 1)
= (x + 1)(x2 - x + 1), which is completely divisible by N, since (x + 1) is divisible by N.
Join the Discussion
Login to post a comment or share your explanation.
Login