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Let $$\root 3 \of a = \root 3 \of {26} + \root 3 \of 7 + \root 3 \of {63} $$ then
Answer & Solution
Correct Answer:
Option
A
$$\eqalign{
& \root 3 \of a = \root 3 \of {26} + \root 3 \of 7 + \root 3 \of {63} \cr
& {\text{Take round figure}} \cr
& \Rightarrow \root 3 \of a < \root 3 \of {27} + \root 3 \of 8 + \root 3 \of {64} \cr
& \Rightarrow \root 3 \of a < 3 + 2 + 4 \cr
& \Rightarrow \root 3 \of a < 9 \cr
& \Rightarrow a < {9^3} \cr
& \Rightarrow a < 729 \cr
& {\text{Option A is answer}} \cr} $$
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