Engineering Mechanics MCQ Questions & Answers

31

If a rigid body is in equilibrium under the action of three forces, then

A) These forces are equal B) The lines of action of these forces meet in a point C) The lines of action of these forces are parallel D) Both (B) and (C) above

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Answer & Solution

Answer: Option D

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32

If a number of forces act simultaneously on a particle, it is possible

A) Not a replace them by a single force B) To replace them by a single force C) To replace them by a single force through C.G. D) To replace them by a couple

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Answer & Solution

Answer: Option B

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33

A rubber ball is dropped from a height of 2 m. If there is no loss of velocity after rebounding, the ball will rise to a height of

A) 1 m B) 2 m C) 3 m D) 4 m

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Answer & Solution

Answer: Option B

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34

The centre of percussion of the homogeneous rod of length ‘L’ suspended at the top will be

A) $$\frac{{\text{L}}}{2}$$ B) $$\frac{{\text{L}}}{3}$$ C) $$\frac{{3{\text{L}}}}{4}$$ D) $$\frac{{2{\text{L}}}}{3}$$

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Answer & Solution

Answer: Option D

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35

The units of moment of inertia of mass are

A) kg-m² B) m²/kg C) kg/m² D) kg/m

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Answer & Solution

Answer: Option A

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36

Mass moment of inertia of a uniform thin rod of mass (M) and length ($$l$$) about its mid-point and perpendicular to its length is

A) $$\frac{2}{3}{\text{M}}{l^2}$$ B) $$\frac{1}{3}{\text{M}}{l^2}$$ C) $$\frac{3}{4}{\text{M}}{l^2}$$ D) $$\frac{1}{{12}}{\text{M}}{l^2}$$

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Answer & Solution

Answer: Option D

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37

Forces are called concurrent when their lines of action meet in

A) One point B) Two points C) Plane D) Perpendicular planes

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Answer & Solution

Answer: Option A

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38

The forces, which meet at one point and their lines of action also lie on the same plane, are known as

A) Coplanar concurrent forces B) Coplanar non-concurrent forces C) Non-coplanar concurrent forces D) Non-coplanar non-concurrent forces

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Answer & Solution

Answer: Option A

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39

If u₁ and u₂ are the velocities of two moving bodies in the same direction before impact and v₁ and v₂ are their velocities after impact, then coefficient of restitution is given by

A) $$\frac{{{{\text{v}}_1} - {{\text{v}}_2}}}{{{{\text{u}}_1} - {{\text{u}}_2}}}$$ B) $$\frac{{{{\text{v}}_2} - {{\text{v}}_1}}}{{{{\text{u}}_1} - {{\text{u}}_2}}}$$ C) $$\frac{{{{\text{u}}_1} - {{\text{u}}_2}}}{{{{\text{v}}_1} - {{\text{v}}_2}}}$$ D) $$\frac{{{{\text{u}}_2} + {{\text{u}}_1}}}{{{{\text{v}}_2} + {{\text{v}}_1}}}$$

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Answer & Solution

Answer: Option B

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40

A body of mass ‘m’ moving with a constant velocity ‘v’ strikes another body of same mass moving with same velocity but in opposite direction. The common velocity of both the bodies after collision is

A) v B) 2v C) 4v D) 8v

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Answer & Solution

Answer: Option B

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Engineering Mechanics MCQ Questions & Answers | Mechanical Engineering