On Children's Day, sweets were to be equally distributed among 175 children in a school. Actually on the Children's Day, 35 children were absent and therefore each child got 4 sweets extra. Total how many sweets were available for distribution ?

Step 1: Let the total number of sweets be = S.

Step 2: If all 175 children were present, each child would get = S ÷ 175 sweets.

Step 3: But 35 children were absent, so only 140 children were present.

Step 4: Now each child got = S ÷ 140 sweets.

Step 5: It is given that each child got 4 more sweets than originally planned.
So, (S ÷ 140) − (S ÷ 175) = 4

Step 6: Take LCM of denominators:
LCM of 140 and 175 = 700.
(S × (5 − 4)) ÷ 700 = 4
S ÷ 700 = 4

Step 7: Therefore, S = 700 × 4 = 2800

Final Answer: Total sweets available = 2800