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Out of the fractions $$\frac{9}{31}$$, $$\frac{3}{17}$$, $$\frac{6}{23}$$, $$\frac{4}{11}$$ and $$\frac{7}{25}$$ which is the largest ?
Answer & Solution
Correct Answer:
Option
D
Converting each of the given fractions into decimal form, we get:
$$\frac{9}{31}$$ = 0.29
$$\frac{3}{17}$$ = 0.176
$$\frac{6}{23}$$ = 0.26
$$\frac{4}{11}$$ = 0.363
$$\frac{7}{25}$$ = 0.28
Clearly, 0.363 > 0.29 > 0.28 > 0.26 > 0.176
So, $$\frac{4}{11}$$ > $$\frac{9}{31}$$ > $$\frac{7}{25}$$ > $$\frac{6}{23}$$ > $$\frac{3}{17}$$
$$\frac{9}{31}$$ = 0.29
$$\frac{3}{17}$$ = 0.176
$$\frac{6}{23}$$ = 0.26
$$\frac{4}{11}$$ = 0.363
$$\frac{7}{25}$$ = 0.28
Clearly, 0.363 > 0.29 > 0.28 > 0.26 > 0.176
So, $$\frac{4}{11}$$ > $$\frac{9}{31}$$ > $$\frac{7}{25}$$ > $$\frac{6}{23}$$ > $$\frac{3}{17}$$
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