ExamVeda
Login
Home
31
What would be the resistance of such a wire in which a 2V potential is applied; the current flowing through the wire is 1 A?
Discuss
Answer & Solution
Answer: Option B
No explanation is given for this question. Let's Discuss on Board
32
Which direction does the freely suspended magnet indicate?
Discuss
Answer & Solution
Answer: Option B
No explanation is given for this question. Let's Discuss on Board
33
Why is tungsten used in electric bulbs?
Discuss
Answer & Solution
Answer: Option B
No explanation is given for this question. Let's Discuss on Board
34
Electric motors operating at low voltages tend to burn out because
Discuss
Answer & Solution
Answer: Option A
No explanation is given for this question. Let's Discuss on Board
35
By which electric current in a circuit is possible?
Discuss
Answer & Solution
Answer: Option D
No explanation is given for this question. Let's Discuss on Board
36
In medicine, . . . . . . . . is a device such as small metal plate or needle that carries electricity from an instrument to a patient for treatment or surgery
Discuss
Answer & Solution
Answer: Option A
No explanation is given for this question. Let's Discuss on Board
37
Identify the correct statement in related to ampere.
Discuss
Answer & Solution
Answer: Option C
No explanation is given for this question. Let's Discuss on Board
38
Electric field strength of charge-
Discuss
Answer & Solution
Answer: Option D
No explanation is given for this question. Let's Discuss on Board
39
Which of the following is not an insulator?
Discuss
Answer & Solution
Answer: Option B
No explanation is given for this question. Let's Discuss on Board
40
Self inductance of a Solenoid is
Discuss
Answer & Solution
Answer: Option C
Solution:
Self-inductance is a property of a coil that opposes changes in the current flowing through it.
Think of it like inertia for electricity!
Several factors affect how much self-inductance a solenoid (a coil of wire) has.

Let's break down why the correct answer is C: directly proportional to area of cross section.
The formula for self-inductance (L) of a solenoid is: L = (μ₀ * N² * A) / l
Where:
μ₀ = permeability of free space (a constant)
N = number of turns in the solenoid
A = area of cross-section of the solenoid
l = length of the solenoid

Now let's look at why the other options are wrong:
Option A: directly proportional to current flowing through the coil - Self-inductance itself doesn't depend on the current. It's a property of the coil, like its resistance. The *voltage* induced *does* depend on the *change* in current.
Option B: directly proportional to its length - The formula shows that self-inductance is *inversely* proportional to the length (l) of the solenoid, not directly proportional. If you make the solenoid longer, keeping everything else the same, the inductance decreases.
Option D: inversely proportional to area of cross-section - The formula clearly shows that self-inductance is *directly* proportional to the area of cross-section (A), not inversely proportional. A larger area allows for more magnetic flux to be created, increasing the inductance.

Therefore, the self-inductance of a solenoid is directly proportional to the area of its cross-section.