$$2\root 3 \of {32} - 3\root 3 \of 4 + \root 3 \of {500} = ?$$
A. $$4\root 3 \of 6 $$
B. $$3\sqrt {24} $$
C. $$6\root 3 \of 4 $$
D. 916
Answer: Option C
Solution (By Examveda Team)
$$\eqalign{ & 2\root 3 \of {32} - 3\root 3 \of 4 + \root 3 \of {500} \cr & = 2\root 3 \of {{2^3} \times 4} - 3\root 3 \of 4 + \root 3 \of {{5^3} \times 4} \cr & = 2 \times 2\root 3 \of 4 - 3\root 3 \of 4 + 5\root 3 \of 4 \cr & = 9\root 3 \of 4 - 3\root 3 \of 4 \cr & = 6\root 3 \of 4 \cr} $$This Question Belongs to Arithmetic Ability >> Surds And Indices
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