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The 3rd and 6th term of an arithmetic progression are 13 and -5 respectively. What is the 11th term?
Answer & Solution
Correct Answer:
Option
D
T3 = a + 2d = 13 ...... (1)
T6 = a + 5d = -5 ...... (2)
on solving (1) and (2) d = -6 & a = 25
T11 = a + 10d
= 25 + 10(-6)
= -35
T6 = a + 5d = -5 ...... (2)
on solving (1) and (2) d = -6 & a = 25
T11 = a + 10d
= 25 + 10(-6)
= -35
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