The arrangement of rational numbers, $$\frac{- 7}{10}$$, $$\frac{5}{- 8}$$, $$\frac{2}{- 3}$$  in ascending order is :

A. $$\frac{2}{{ - 3}},\frac{5}{{ - 8}},\frac{{ - 7}}{{10}}$$

B. $$\frac{5}{{ - 8}},\frac{{ - 7}}{{10}},\frac{2}{{ - 3}}$$

C. $$\frac{{ - 7}}{{10}},\frac{5}{{ - 8}},\frac{2}{{ - 3}}$$

D. $$\frac{{ - 7}}{{10}},\frac{2}{{ - 3}},\frac{5}{{ - 8}}$$

Answer: Option D

Solution(By Examveda Team)

$$\frac{- 7}{10}$$ = - 0.7
$$\frac{5}{- 8}$$ = - $$\frac{5}{8}$$ = - 0.625,
$$\frac{2}{- 3}$$ = - $$\frac{2}{3}$$ = - 0.66
Since, -0.7 < -0.66 < -0.625
So, $$\frac{- 7}{10}$$ < $$\frac{2}{- 3}$$ < $$\frac{5}{- 8}$$