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The common difference of the A.P. $$\frac{1}{{2b}},$$ $$\frac{{1 - 6b}}{{2b}},$$ $$\frac{{1 - 12b}}{{2b}},$$ . . . . . is
Answer & Solution
Correct Answer:
Option
D
$$\eqalign{
& A.P.\,is\,\frac{1}{{2b}},\,\frac{{1 - 6b}}{{2b}},\,\frac{{1 - 12b}}{{2b}},.... \cr
& \Rightarrow \frac{1}{{2b}},\,\frac{1}{{2b}} - \frac{{6b}}{{2b}},\,\frac{1}{{2b}} - \frac{{12b}}{{2b}},\,.... \cr
& \Rightarrow \frac{1}{{2b}},\,\frac{1}{{2b}} - 3,\,\frac{1}{{2b}} - 6,\,.... \cr
& \therefore d = \frac{1}{{2b}} - 3 - \frac{1}{{2b}} = - 3 \cr} $$
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