The equivalent diameter for fluid flow through square cross section channel of side 'x', for pressure drop calculation purpose is given by

A. Thermal conductivity B. Electrical conductivity C. Specific gravity D. Electrical resistivity

A. $$\frac{{\text{V}}}{{{{\text{V}}_{\max }}}} = {\left( {\frac{{\text{x}}}{{\text{r}}}} \right)^{\frac{1}{7}}}$$ B. $$\frac{{\text{V}}}{{{{\text{V}}_{\max }}}} = {\left( {\frac{{\text{r}}}{{\text{x}}}} \right)^{\frac{1}{7}}}$$ C. $$\frac{{\text{V}}}{{{{\text{V}}_{\max }}}} = {\left( {{\text{x}} \times {\text{r}}} \right)^{\frac{1}{7}}}$$ D. None of these

A. d B. $$\frac{1}{{\text{d}}}$$ C. $$\sigma $$ D. $$\frac{l}{\sigma }$$

A. $$\frac{{4\pi {\text{g}}}}{3}$$ B. $$\frac{{0.01\pi {\text{gH}}}}{4}$$ C. $$\frac{{0.01\pi {\text{gH}}}}{8}$$ D. $$\frac{{0.04\pi {\text{gH}}}}{3}$$