The factors of x2 + 4y2 + 4y - 4xy - 2x - 8 are:
A. (x - 2y - 4)(x - 2y + 2)
B. (x2 - 2y - 4)(x2 - 2y + 2)
C. (x + 2y - 4)(x + 2y + 2)
D. (x2 - 2y - 4)(x2 + 2y + 2)
Answer: Option A
Solution(By Examveda Team)
x2 + 4y2 - 4xy + 4y - 2x - 8= (x - 2y)2 - 2(x - 2y) - 8
put y = (x - 2y)
= y2 - 2y - 8
= y2 - 4y + 2y - 8
= y(y - 4) + 2(y - 4)
= (y - 4)(y + 2)
= (x - 2y - 4)(x - 2y + 2)
This Question Belongs to Arithmetic Ability >> Algebra
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