The front axle of a car has pivot centers 1.3 m apart. The angle of inside lock is 40! and the angle of the outside lock is 35!. What is the wheelbase of the car?

A) 5.5 m B) 3.5 m C) 4.5 m D) 6.5 m

Answer & Solution

Correct Answer: Option A

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Question posted by Examveda

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3 Comments

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Naveen Kumar 3 years ago

If the wheelbase, the pivot center, and wheel track of the are 2.5 m, 1.1 m, and 1.3 m respectively. The angle of the inside lock is 42℃. What is the circle radius of the outer front wheel?

Divya R 3 years ago

cot fie-cot thita = c/b
cot 35- cot 40 = 1.3/b
b= 5.49

Divya R 3 years ago

cot pie-cot thita = c/b
cot 35-cot40 = 1.3/b
b= 0.5

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The front axle of a car has pivot centers 1 3...

The front axle of a car has pivot centers 1.3 m apart. The angle of inside lock is 40! and the angle of the outside lock is 35!. What is the wheelbase of the car?

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