The front axle of a car has pivot centers 1.3 m apart. The angle of inside lock is 40! and the angle of the outside lock is 35!. What is the wheelbase of the car?
A. 5.5 m
B. 3.5 m
C. 4.5 m
D. 6.5 m
Answer: Option A
This Question Belongs to Automobile Engineering >> Introduction Of Automobile
If the wheelbase, the pivot center, and wheel track of the are 2.5 m, 1.1 m, and 1.3 m respectively. The angle of the inside lock is 42℃. What is the circle radius of the outer front wheel?
cot fie-cot thita = c/b
cot 35- cot 40 = 1.3/b
b= 5.49
cot pie-cot thita = c/b
cot 35-cot40 = 1.3/b
b= 0.5